Glenbeulah, Wisconsin

From Wikipedia, the free encyclopedia

Glenbeulah is a village in Sheboygan County, Wisconsin, along the Mullet River. The population was 378 at the 2000 census. It is included in the Sheboygan, Wisconsin Metropolitan Statistical Area.

[edit] Geography

Glenbeulah is located at 43°47′48″N, 88°2′45″W (43.796630, -88.045834)^GR1.

According to the United States Census Bureau, the village has a total area of 1.8 km² (0.7 mi²). 1.7 km² (0.7 mi²) of it is land and 1.45% is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 378 people, 153 households, and 108 families residing in the village. The population density was 217.8/km² (563.2/mi²). There were 160 housing units at an average density of 92.2/km² (238.4/mi²). The racial makeup of the village was 99.47% White, 0.53% from other races. Hispanic or Latino of any race were 0.53% of the population.

There were 153 households out of which 33.3% had children under the age of 18 living with them, 61.4% were married couples living together, 6.5% had a female householder with no husband present, and 29.4% were non-families. 22.9% of all households were made up of individuals and 7.8% had someone living alone who was 65 years of age or older. The average household size was 2.47 and the average family size was 2.97.

In the village the population was spread out with 24.1% under the age of 18, 7.1% from 18 to 24, 33.6% from 25 to 44, 22.8% from 45 to 64, and 12.4% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 103.2 males. For every 100 females age 18 and over, there were 99.3 males.

The median income for a household in the village was $42,656, and the median income for a family was $47,045. Males had a median income of $32,411 versus $20,568 for females. The per capita income for the village was $17,240. None of the families and 1.9% of the population were living below the poverty line, including no under eighteens and 10.3% of those over 64.